Tom_hampton wrote:
Quote:
There is one other fundamental to track running that may fully
overcome the CoG distance and other effects The actual runner's foot-path is piecewise linear, so, the runner's feet are really following a hectogon and applying a lateral force (in addition to the downward one...or perhaps a rotation, followed by a longitudinal thrust) to impart the 3.6* course change per step. Due to inertial effects and the generally sloppy, human form the CG path will still be mostly round, as the vertices will round off.
I concur with the
bold above. Fundamentally, my point with the Coriolis discussion is that even the half-sided effect is several orders of magnitude down (about 5) from these measurable human scale effects, such as you discuss above. With symmetry it is effectively eliminated.
That's a good point about the rounding off of the CoG shape, probably had a sizeable effect on the turning force just by spreading the load over time. There is also the next inferred point that the CoG polygon can legally cross over the inside of the lane freely, so long as the vertices (footfalls) land outside of it.
I was on a lunch run thinking about this and I think there's a simple way to approximate the turning losses.
A runner maintaining an even effort can expect that a uniform step put into the ground (force*time) will yield a uniform stride length. Assume 2m per stride and we can triangulate a simple turning model. Since the force from the previous step is 3.6deg different than the next, we can say the aparrent forward vector (hypotenuse) on the straights is 2 and the vertex angle is 3.6deg, the perpendicular inward motion vector of 0.125m/step must be added. The motion vector has to remain 2 since it's a constant effort, so the actual forward motion vector is 1.996, 99.8% of the apparent. The forward motion is compromised by 0.2% on the turns but not the straights, half the race, leaving the turning loss at ~0.1%, We've shown a track 10k on the measurement line is actually 9,992.4m, 0.076% less, wildly close to the 0.1% above.
I'm not sure if the assumptions going into these calcs are correct, but there's some very smart people on this thread and I'm happy to be corrected. Just fun to nerd out for a minute.