Power Estimation from IM bike split

Triathlon Forum
1

I now train and race using a powermeter, and I have a good understanding of where I am now and what power I’m capable of sustaining in up coming races. However, I’ve always been intrigued about what power I was producing in the past.

Can anyone estimate the power required to produce a 5:32 bike split at Florida and a 5:36 in Canada. I’m 5’10 and was 154lb at the time and had (in my opinion) had a pretty aero position.

Thanks

Jon

2

Hi Jon:

Here is a link to a new calculator I am currently working on: http://www.triathloncalculator.com/TEST/. Back out the power required to get the race times you have data for. Use these elevation inputs while doing so:

IMFL: 10
IMC: 75

I hope this helps. Thanks!

-Jesse

3

I tried out your calculator very cool but I think the bike time is a little slow and the Watts a little high. I used 50 for IMCDA

4

Hi -

I used your calculator and it was right on for Lake Placid. Do you have a function for wind and heat? Hawaii was off!

5

What year did you do IMFL? I’m about your size (5’11", 152@ race weight) and I rode 5:29 at IMFL in 2006 with an AP of 170 .

6

what elevation did you use for IMLP?

7

I am about 145 lbs and rode 5:05-5:15 at IMC with avg power of 180 with SRM
.

8

Try these site…they work great…i keyed in my Normalized power and the split was off by 10 seconds from actual ride time.

http://www.kreuzotter.de/english/espeed.htm

or

http://bikecalculator.com/veloUS.html

9

…but your avg speed (and hence ride time) isn’t based on Np, rather Average Power.

10

You are correct…not sure why NP works but it does…AP and NP were actually pretty close as this is a flat course
.

11

I would say 170 to go 5.5 in florida is about right (alot depends on how aero you are and how much drafting you do of course) I have consistantly
gone 5hrs - 5.10 and my power averages have been just 200-215/
.