If a rider goes 27.5mph @ 267 watts and 137lbs @ 5’10"
How many watts should a 173lbs rider @ 6’3" require to go the same speed
Assume identical equipment, similar positions.
annnd discuss!
I don’t know the answer, but I know a 5-9 person can do the same while weighing 170
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I don’t know the answer, but I know a 5-9 person can do the same while weighing 170
probably not in the same conditions =)
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Gotta know how hilly, right?
You can’t compute that from just the data you gave.
actually, probably, unless extra hilly, wind not the issue
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Gotta know how hilly, right?
You can’t compute that from just the data you gave.
rolling hills, out and back so no net elevation difference. no big climbs. all big ring =)
305 watts
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so just going by watts/kg
the 173lbs hypothetical person would need to do 335 watts.
fffffffuuuuu
wtf does w/kg have to do with aero??? 
that is serious Jack and you know it! how can an aero weenie ask such questions?
wtf does w/kg have to do with aero???
given similar positions, it is a rough proxy. a starting point
that is serious Jack and you know it! how can an aero weenie ask such questions?
very serious, we need peer review
only in an uphill TT, you know you really want W/m^2
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only in an uphill TT, you know you really want W/m^2
indeed I do.
now to measure these hypothetical people’s m^2…
323.31 +/- .2 W
Lets assume that its flat, and 80% of the drag is coming from the rider, so for the bike to go that fast by itself it needs 53.4 W. Rider 1 is 1.95 lb/ft, and Rider 2 is 2.3 lb/ft, so Rider2 needs to lose some weight. The ratio of that is 1.179. If we also assume that the drag is going to increase proportionally to both weight and height, then the drag for Rider2 is that of Rider 1 without the bike (213 W) times our ratio squared => 269.91 plus the bike is 323.31.
Hmm…
lets see…throw a bunch of numbers ot in long rambling sentence and call it a conclusion. hmmmmm
assuming rider 1 is somewhat aero, based upon numbers, maybe 72% is rider, tops, now recalc please
That much weight matters, but its a simple calc on Analytical Cycling. That leaves you with estimating the aero hit, which is likely bigger. The trouble is I don’t think “similar postion” is particularly realistic. Some bigger guys may be more aero than smaller guys. Its not likely but its also not linear, particularly if the 2 guys have differing leg to torso length ratios.
That said I’d go 10% more frontal area on the bigger guy and use that as an input in AC.
just use that graph from Rchung listed in various threads for w/m^2 and power/speed put rides infrom both riders and then est, assuming all else equal. left filed/right field, somewhere in teh ballpark
Now that I look at the “theoretical” people I think I smell a bet with the Mrs. If my guess is correct, rethink the whole process, if you lose you lose, if you win, well you still lose. 
Dude, are these only pure “hypotheticals”, or is the spousal unit really slapping you around that badly (and you’re merely trying to quantify your emasculation, for strictly scientific purposes of course)?
Oh, and are you sure that power meter is correct?
Or will you be using the same wheel in which case it doesn’t matter?
I don’t know the answer, but your wife is fast. Nice job by both of you tonight.
Off topic question, I set a PR out there by over a minute. A big part of that was my recent cycling block, but I can’t help but wonder how much was just because the wind direction was better than usual tonight. It seemed like lots of tailwind on the way out (on the west headed part anyway) where I usually struggle. How did your times tonight compare with your norm? PRs or close to it?