OK stupid question but I am doing a ride tomorrow that has one climb that is 3150’ of elevation and is 11.32 miles. What is average grade? If this equals 278.27’ per mile and a mile is 5280’ then don’t you just divide 278.27 by 5280 to get 5.27%? Here is elevation map: http://www.srcc.com/profiles_html/pine_flat_rd.HTM
Don’t ask me about the math- I don’t even understand this part:
Total climb in forward direction: 3150 feet
Total climb in reverse direction: 201 feet
It’s uphill in both directions?
What that means is there are some uphill sections going both ways but the forward direction is the predominant climb. Way steeper than that road that goes by your place!
Ah. OK. Then shouldn’t you put in the net climb for the calculation- what, about 2950 feet?
grade (in %) = 100*height / sqrt(travel^2 - height^2) = 5.3%.
OK stupid question
Average grade is simply rise over run, multiplied by 100 to get a percentage.
e.g. total climbing (rise) divided by distance (run), x 100
For example, if you ride 100 ft, with 50ft of evelation gain over that distance, your grade for that section is 50%.
For example, if you ride 100 ft, with 50ft of evelation gain over that distance, your grade for that section is 50%.
That must be what the hills of Auburn are like.
.
Pretty close, gradient is simply slope expressed as a percentage. Vertical distance divided by horizontal distance (multiply by 100 if you wish).
-C
however, the distance measured by the cycling computer is not the “run”, it is the hypotenus (sp?).
a^2 + b^2 = c^2
you have to solve for the “run”
c^2 or c squared is the distance measured on your computer squared.
b^2 or b squared is the vertical displacement squared (use the same units)
a^2 or a squared is the horizontal displacement squared or the “run” squared
you have the values for c and b, you have to solve for a.
then take b/a and you have the rise over the run, which gives you the slope.
Screw all that math stuff…
Do what all the hipsters are doin’ and let someone else do the thinkin’ fer ya…
OK stupid question
Average grade is simply rise over run, multiplied by 100 to get a percentage.
e.g. total climbing (rise) divided by distance (run), x 100
For example, if you ride 100 ft, with 50ft of evelation gain over that distance, your grade for that section is 50%.
You have to be very careful in your calculation. In your example, the grade is actually 58%. This is assuming your rollout distance is 100 feet. You are assuming the rollout distance is the same as the “run” and it is not.
however, the distance measured by the cycling computer is not the “run”, it is the hypotenus (sp?).
you have to solve for the “run”
Unless I’m wrong, we’re not talking about using the hypotenus. In this case, the OP is asking about the grade - he knows the elevation gain (rise), and the ‘flat’ vertical distance covered (run). This should be a simple rise over run calculation. The info is taken from a map, not a cycling computer.
Well that certainly makes a difference. I was not clear what he was using to determine the 11.xx miles. I just wanted to point out that the odometer distance is different that run. Many people fail to make the distinction. For many climbs, the difference is nearly negligible. What someone thought was 6.2% might really have been 6.8%.
This does lead me to wonder how the distance is calculated on a map such as mapquest or gmap’s pedometer. Do those account for hills, or are they simply giving what the linear distance would be without hills?
To add to your edification, road signs post the maximum grade not the average.