The idea is to take four given numbers, and, using those numbers in any order in combinations of addition, subtraction, multiplication and division, come up with an equation that equals 24. I’d never seen it before yesterday, when my math teacher wife brought one home from school.
For example, 4/7/8/8 might yield 4 * (7 - (8/8)) = 24.
Here’s a harder one: 7, 11, 17 and 20.
Easy.
20 + (11-7)/(17/17) = 24
I do this stuff in my head on long runs/rides – my mental training.
Isn’t that basically the same thing as the Ken Ken game that you posted a couple of weeks ago.
Are you restricted to one use of the number? 17 was used twice in the solution below.
Fun game. I haven’t read the entire rule book, but is using one of the numbers as you did twice, allowed? The OP did it because 8 was listed twice.
The idea is to take four given numbers, and, using those numbers in any order in combinations of addition, subtraction, multiplication and division, come up with an equation that equals 24. I’d never seen it before yesterday, when my math teacher wife brought one home from school.
For example, 4/7/8/8 might yield 4 * (7 - (8/8)) = 24.
Here’s a harder one: 7, 11, 17 and 20.
20 + ((11+17)/7) = 24
Fun.
Ah, good point. I didn’t realize that “8” was given twice in the first example.
Fun game: Here is my solution:
23.14-(122.12)^2/2/9(2-.3((3/.32)+3*.23)^-.23)*infinity = Obama Sucks!
Thanks, I was afraid that the suckiness of Obama was not going to be brought up in this thread.
.
My school always has a tournament for this in 4 th grade! I LOVED this game.
If reuse of numbers is allowed then it is trivial for arbitrary numbers a, b,c, d
24 = ( (a+a+a)/a)((a+a)/a)((a+a)/a)*((a+a)/a) )
How about this, find an algorithm that returns the expression with minimum number of operator usage.