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Math puzzle

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duffman

Jul 18, 12 13:57

Post #51 of 63 (523 views)
klehner wrote:
So what would be the answer for, say, 51?

seems it's n+1 for a prime, and the minimum of the prime factors otherwise, so 3^1 * 17^1 means

min(f(3), f(17) = min(4, 18) = 4

i'm perplexed by 11 and 13 are you sure those are right?
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duffman

Jul 18, 12 13:59

Post #52 of 63 (520 views)
if you wrote a computer program to do this, then shame on you. that's a very boring way to solve this sort of problem!
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klehner

Jul 18, 12 14:03

Post #53 of 63 (518 views)
duffman wrote:
klehner wrote:
So what would be the answer for, say, 51?

seems it's n+1 for a prime, and the minimum of the prime factors otherwise, so 3^1 * 17^1 means

min(f(3), f(17) = min(4, 18) = 4

i'm perplexed by 11 and 13 are you sure those are right?

Fat fingered, since corrected. The concise solution for n x n is p + 1, where p is the smallest prime factor of n.
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Of course, with your ears stuffed with outrage cotton balls, all you heard was, rahrahra, govt comes to get your guns, rhahrahrah, stamp out your FREEEEEDOM! - slowguy

duffman

Jul 18, 12 14:07

Post #54 of 63 (516 views)
well done sir. how about the more general case, i.e. the class isn't a perfect square (e.g. 60 grouped into 10s)? i'm not going to think about about that one...
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BarryP

Jul 19, 12 6:47

Post #55 of 63 (475 views)
6 classes of 10? That shouldn't be hard now that we've worked through the last one.
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duffman

Jul 19, 12 7:24

Post #56 of 63 (463 views)
Do the math and let me know the answer...I'm a bit too lazy
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BarryP

Jul 19, 12 9:28

Post #57 of 63 (441 views)
I started, realized it was a tad more complicated, and then thought, "I really shouldn't blow another afternoon at work!"

; ^ )
-----------------------------Baron Von Speedypants
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BarryP

Jul 19, 12 10:13

Post #58 of 63 (430 views)
Okay, the answer to 6 classes of 10 is 1 Day. If you have 10 people in one class, you have to have at least 10 classes in order to disperse the entire class into 10 differetnt classes on the next day.

So the better question would be 10 classes of 6.
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duffman

Jul 19, 12 10:33

Post #59 of 63 (426 views)
Right. Thought you weren't going to waste a work day :)

So then 10 classes of six?
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Eppur si muove

Jul 24, 12 5:51

Post #60 of 63 (340 views)
Unless I'm missing something, the longest number of days for 4x4 is at least 4, not 3:

ABCD EFGH IJKL MNOP
AEIM BFJN CGKO DHLP
AFKP BELO CHIN DGJM
AGLN BHKM CEJP DFIO

(This post was edited by Eppur si muove on Jul 24, 12 6:05)

Eppur si muove

Jul 24, 12 6:54

Post #61 of 63 (320 views)
 Re: Math puzzle [Eppur si muove] [In reply to] Quote | Reply
Actually, make that 5 days! One more day can be added to the above, as follows:

AHJO BGIP CFLM DEKN

I think someone has already pointed out why it would be impossible to go further than 5 days for 4x4=16 people.

klehner

Jul 24, 12 7:00

Post #62 of 63 (318 views)
 Re: Math puzzle [Eppur si muove] [In reply to] Quote | Reply

AHJO BGIP CFLM DEKN

For n+1 for a non-prime number.

As this puzzle comes from the NYTimes, I submitted this as a comment.

http://wordplay.blogs.nytimes.com/...ners/?ref=crosswords
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Of course, with your ears stuffed with outrage cotton balls, all you heard was, rahrahra, govt comes to get your guns, rhahrahrah, stamp out your FREEEEEDOM! - slowguy

Eppur si muove

Jul 24, 12 7:16

Post #63 of 63 (310 views)