Well, your money is on a plagiarist - he stole that rant from the third to last post in this thread:
https://bicycles.stackexchange.com/...e-go-downhill-faster shameful. And he then failed to read the final post.
Greater mass has an easier time overcoming wind resistance, but as I referenced in my previous comment on inertia, wind speed and direction and rider direction relative to the wind are not constant, so there a lot of forces trying to change the rider's state of motion (a straight line) and those forces make the lighter rider slower. Toss in some technical turns, and the heavier rider is at a disadvantage. (*My own words)
And here's that final post for you - in quotations, like any good and descent human would do, especially one posing anonymously as an intellectual on a forum ;)
"As usual, I think the best way to consider this is through energy;
in moving from rest at the top of a hill (height h), the conservation of energy applies between potential energy at the top and kinetic at the bottom:
Mgh = MV^2 + losses(due to aero and rolling resistance)
therefore
V = sqrt( gh - losses/M )
as losses are not proportional to mass, then factoring them down by mass reduces their influence on speed for the heavier rider, regardless of whether terminal velocity has been reached or not"
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